解:,∴f(x)在[0,3]上递增,·········································· 2分 证明:f(x+h)-f(x)=,······················· 6分 ∵x + h,x∈[0,3], ∴x + h + 1 > 0,x + 1 > 0,························································ 8分 又∵h > 0, ∴f ( x + h)- f (x)> 0,········································· 9分 ∴f (x) 在[0,3] 上递增.······················································· 10分 |