2aL1 |
Em |
R |
nBL2
| ||
R |
. |
I |
| ||
R |
△ϕ |
△t |
△t |
R |
△ϕ |
R |
nBL1L2 |
R |
1 |
2 |
I | 2m |
L1 |
v |
n2B2
| ||||
R |
n2B2
| ||||
R |
|
nBL2vt |
R |
P |
vt |
n2B2L22a2 |
R |
|
2aL1 |
|
|
d-L1 | ||
|
2an2B2L1L22 |
R |
2aL1 |
|
d-L1 | ||
|
|
d | ||
|
nBL2
| ||
R |
nBL1L2 |
R |
n2B2
| ||||
R |
n2B2L22a2 |
R |
|
2aL1 |
|
|
d-L1 | ||
|
2an2B2L1L22 |
R |
2aL1 |
|
d-L1 | ||
|
|
d | ||
|
A.线框电阻越大,外力做功越多 |
B.线框速度越大,外力做功越多 |
C.线框速度越大,外力做功功率越大 |
D.线框速度越大,通过线框某一截面的电量越多 |
R |
2 |
A.若ab棒匀速运动,则IR≠0,Ic=0 |
B.若ab棒匀速运动,则IR=0,Ic=0 |
C.若ab棒在某一中心位置两侧做往复运动,则IR≠0,Ic≠0 |
D.若ab棒做匀加速运动,则IR≠0,Ic=0 |
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