利用升压变压器和降压变压器,实现远距离高压输电,如果发电机的输出电压不变,则下列叙述中正确的是( )A.升压变压器的原线圈中的电流与用户用电设备消耗的功率无关 | B.输电线路中的电流只由升压变压器原副线圈的匝数比决定 | C.当用户用电器的总电阻减小时,输电线上损失的功率增大 | D.升压变压器的输出电压等于降压变压器的输入电压 |
答案
举一反三
如图所示为一理想变压器,原线圈的输入电压 U 1=3300V,副线圈的输出电压 U2=220V,绕过铁心的单匝导线的电压表的示数为U0=2V,两个相同的灯泡并连接在副线圈上,则: ( l )原、副线圈的匝数各是多少? ( 2 )当 S 断开时,A 2的示数I2=5A,那么 A1的示数是多少? ( 3 )当 S 闭合时,变压器原线圈的输入功率为多大?(导线电阻忽略不计)![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200116/20200116220044-65909.png) | 某理想变压器原线圈输入电功率为P,原、副线圈匝数比为k,在副线圈上接一内阻为r的电动机,电动机正以速度v匀速向上提升质量为m的重物,已知重力加速度为g,则变压器初级线圈两端的电压为( )
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| A.PK![](data:image/png;base64,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) | B.![](data:image/png;base64,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) | C.Pk![](data:image/png;base64,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) | D.![](data:image/png;base64,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) | 某小型水电站的电能输送示意图如下,发电机的输出电压为200V,输电线总电阻为r,升压变压器原副线圈匝数分别为n1、n2,降压变压器原副线圈匝数分别为n3、n4(变压器均为理想变压器).要使额定电压为220V的用电器正常工作,则下列说法正确的是( ) ①n2/n1>n3/n4 ②n2/n1<n3/n4 ③升压变压器的输出电压等于降压变压器的输入电压 ④升压变压器的输出功率大于降压变压器的输入功率.A.①③ | B.①④ | C.②③ | D.②④ | 交流发电机的发电原理是矩形线圈在匀强磁场中绕垂直于磁场的轴OO’匀速转动.一小型发电机的线圈共220匝,线圈面积S=0.05m2,线圈转动的频率为50Hz,线圈内阻不计,磁场的磁感应强度B=T.为用此发电机所发出交流电带动两个标有“220V 11kW”的电机正常工作,需在发电机的输出端a、b与电机之间接一个理想变压器,电路如图.求: (1)发电机的输出电压为多少? (2)变压器原副线圈的匝数比为多少? (3)与变压器原线圈串联的交流电流表的示数为多少?
![魔方格](http://img.shitiku.com.cn/uploads/allimg/20200116/20200116220023-53613.png)
| 如图所示,L1和L2是输电线,甲是电压互感器,乙是电流互感器.若已知变压比为1 000:1,变流比为100:1,并且知道电压表示数为220V,电流表示数为10A,则输电线的输送功率为( )A.2.2×103W | B.2.2×10-2W | C.2.2×108W | D.2.2×104W |
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