y= √[x√(x√x)] + 1 / √[x√(x√x)] 怎么求导?

题目

y= √[x√(x√x)] + 1 / √[x√(x√x)] 怎么求导?
都是根号,一层包一层
√[x√(x√x)] 就是 [ x 乘上 (x乘以根号x)开的根号 ]再开根

答案

y=x^(7/6)+x^(-7/6)
y`=7/6x^(1/6)-7/6x^(-13/6)