y=x除以根号下x^2+1的微分.

题目

y=x除以根号下x^2+1的微分.

答案

dy=d(x/√(x^2+1))
={√(x^2+1)*dx-x*2x/[2√(x^2+1)]dx}/(x^2+1)
=1/(x^2+1)^(3/2)*dx