java&Android 判断num1和num2为空的状态正常运行new Task_SearchCars这句的内容且num1和num2值分别为.

题目

java&Android 判断num1和num2为空的状态正常运行new Task_SearchCars这句的内容且num1和num2值分别为.
判断num1和num2为空的状态正常运行new Task_SearchCars这句的内容
且判断当num1和num2值分别为“最小载重” “最大载重”时,最小载重和最大载重均变为空,然后继续正常运行new Task_SearchCars这句的内容
x09x09public void onClick(View v) {
x09x09x09String areaIdStr = Cars_Start.getText().toString().trim();//
x09x09x09String areaIdStr2 = Cars_End.getText().toString().trim();//
x09x09x09String vnameIdStr = SearchCarsType.getText().toString();
x09x09x09String num1 = zaizhong1.getSelectedItem().toString();
x09x09x09String num2 = zaizhong2.getSelectedItem().toString();
x09x09x09if(Integer.valueOf(num1) > Integer.valueOf(num2))
x09x09x09{
x09x09x09x09Toast.makeText(SearchCarsActivity.this,"请注意载重值的大小",1000).show();
x09x09x09x09return;
x09x09x09}
x09x09x09new Task_SearchCars(SearchCarsActivity.this,mHandler,
x09x09x09x09x09Constants.CARSLIST_URL + "&area1=" + areaIdStr + "&area2="
x09x09x09x09x09+ areaIdStr2 + "&vtypes=" + "&VehicleType

答案

题目没看懂；试问Task_SearchCars是否继承自Asynctask,重复多次点击之后会不会卡?
这种情形下,我觉得用Handler + Thread应该会好点.虽然你是把handler作为变量给了Task_SearchCars~~