当x=根号2004-1时,求(x+1)²-6的值

题目

当x=根号2004-1时,求(x+1)²-6的值

答案

(x+1)²-6=x²+2x+1-6

= x²+2x-5

=(√2004-1)²+2×(√2004-1)-5

=2004-2√2004 +1 +2√2004-2-5

=2004 -6

=1998