9/8[2/3(4/5x-2/3)+1]=2/3(1/2-1/3)x-5/8 去括号解一元一次方程

题目

9/8[2/3(4/5x-2/3)+1]=2/3(1/2-1/3)x-5/8 去括号解一元一次方程

答案

理解为如下表达式：
(9/8)[(2/3)(4x/5-2/3)+1]=(2/3)(1/2-1/3)x-5/8
(9/8)[(2/3)(4x/5-2/3)+1]=(1/9)x-5/8
[(2/3)(4x/5-2/3)+1]=[(1/9)x-5/8](8/9)
[(2/3)(4x/5-2/3)+1]=[(8/81)x-5/9]
(2/3)(4x/5-2/3)+1=(8/81)x-5/9
8x/15-4/9+1=8x/81-5/9
8x(1/15-1/81)=4/9-1-5/9
8x[1/(3*5)-1/(3*27)]=-10/9
8x[(27-5)/(5*3*27)=-10/9
4x[(22)/(5*3*27)=-5/9
x=(-5)*(5*3*3)/88
x=-225/88