化简:(1)5m﹣7n﹣8p+5n﹣9m﹣p;(2)(5x2y﹣7xy2)﹣(xy2﹣3x2y);(3)3(﹣3a2﹣2a)﹣[a2﹣2(5a﹣4a2+1)﹣3
题型:解答题难度:一般来源:江苏省期中题
化简: (1)5m﹣7n﹣8p+5n﹣9m﹣p; (2)(5x2y﹣7xy2)﹣(xy2﹣3x2y); (3)3(﹣3a2﹣2a)﹣[a2﹣2(5a﹣4a2+1)﹣3a]. |
答案
解:(1)原式=(5﹣9)m+(﹣7+5)n﹣(8+1)p =﹣4m﹣2n﹣9p; (2)原式=5x2y﹣7xy2﹣xy2+3x2y =(5+3)x2+(﹣7﹣1))xy2 =8x2y﹣8xy2; (3)原式=3(﹣3a2﹣2a)﹣[a2﹣10a+8a2﹣2﹣3a] =﹣9a2﹣6a﹣9a2+13a+2 =﹣18a2+7a+2. |
举一反三
先化简,再求值: (1)(2x3﹣3x2﹣3)﹣(﹣x3+4x2),其中x=﹣1. (2)已知(a+2)2+|b﹣|=0,求5a2b﹣[2a2b﹣(ab2﹣2a2b)﹣4]﹣2ab2的值. |
2(a+3b)﹣3(a﹣b) |
先化简,再求值:﹣(a2﹣6ab+9)+2(a2+4ab﹣4.5),a=﹣,b=6. |
下列合并同类项正确的是 |
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A.3+2ab=5ab B.5xy﹣x=5y C.﹣5mn2+5n2m=0 D.a3﹣a=a2 |
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