计算:(1)(-13)-1+(-2)3×(π-2)0;(2)(a+1)2-2(a+1)(a-1)-6.
题型:解答题难度:一般来源:不详
计算: (1)(-)-1+(-2)3×(π-2)0; (2)(a+1)2-2(a+1)(a-1)-6. |
答案
(1)原式=-3-8×1=-11; (2)原式=a2+2a+1-2(a2-1)-6=a2+2a+1-2a2+2-6=-a2+2a-3. |
举一反三
计算题 (1)(-)0-22×0.25+2-1 (2)a-a2-a3+(-2a)3-a8÷a2. |
计算: (1)-22+30-(-)-1 (2)(-2a)3-(-a)-(3a)2 (3)(x+2)2-(x-1)(x-2) (4)(a+b)2(a-b)2 (5)(a-3)(a+3)(a2+9) (6)(m-2n+3)(m+2n-3) |
()-3=______,(-2)0+(-2)2=______. |
计算或化简: (1)()-1+(-1)3+(2011)0 (2)(a+1)2-2(a+1)(a-1)-6 (3)a-a2-a3+(-2a3)2-a8÷a2 (4)(a-b+1)(a+b-1) |
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