若4x2+3x-16除以一多项式,得商式为x+2,余式为-6,则此多项式是( )A.4x-5B.4x-11C.4x3+11x2-10x-26D.4x3+11x
题型:单选题难度:简单来源:台湾
若4x2+3x-16除以一多项式,得商式为x+2,余式为-6,则此多项式是( )A.4x-5 | B.4x-11 | C.4x3+11x2-10x-26 | D.4x3+11x2-10x-38 |
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答案
根据题意,[(4x2+3x-16)-(-6)]÷(x+2), =(4x2+3x-10)÷(x+2), =(x+2)(4x-5)÷(x+2), =4x-5. 故选A. |
举一反三
下列运算正确的是( )A.(am+bm+cm)÷n=am÷n+bm÷n+cm÷n=++ | B.(-a3b-14a2+7a)÷7a=-7a2b-2a | C.(36x4y3-24x3y2+3x2y2)÷(-6x2y)=-6x2y+4x5y3-x4y3 | D.(6am+2bn-4am+1bn+1+2ambn+2)÷(-2ambn)=-3a2+2ab-bn+1 |
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计算:(-x2y2-2xy)÷(-xy)=______;(-8mn+2-4m2)÷(-2m)2=______. |
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