计算:(1)[(-x2y)3]2-(-xy2) (2)-(a2b+4ab-2)+2(a2-3ab+2)(3)[(x+1)(x+2
题型:解答题难度:一般来源:不详
计算: (1)[(-x2y)3]2-(-xy2) (2)-(a2b+4ab-2)+2(a2-3ab+2) (3)[(x+1)(x+2)-2]÷x. |
答案
(1)原式=x12y6•(-xy2) =-x13y8;
(2)原式=-a2b-4ab+2+2a2-6ab+4 =-a2b+2ab+6+2a2;
(3)原式=(x2+3x)÷x =x+3. |
举一反三
先化简,再求值:(3x2+4y)-(3x2+5y-3)-(-2x2-5y+5),其中x=-3,y=-4. |
计算: (1)-+; (2)2x2y•(-3xy)÷(xy)2; (3)(-2a)•(3a2-a+3); (4)(x+3)(x+4)-(x-1)2; (5)(x4+2x3-x2)÷(-)2. |
求代数式3x2y-[2xy2-2(xy-x2y)+xy]+3xy2的值,其中x=3,y=-. |
化简: (1)5a2-[a2+(5 a2-2a)-2(a2-3a)]; (2)-{-[-(-a2)-b2]}-[-(-b)2]. |
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