把下列各式分解因式:(1)x3+x2y-xy2-y3;(2)(a2+2)(a2+1)-30.
题型:解答题难度:一般来源:不详
把下列各式分解因式: (1)x3+x2y-xy2-y3; (2)(a2+2)(a2+1)-30. |
答案
(1)x3+x2y-xy2-y3
| =(x3+x2y)-(xy2+y3) | =x2(x+y)-y2(x+y) | =(x+y)(x2-y2) | =(x+y)(x+y)(x-y) | =(x+y)2(x-y) |
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(2)(a2+2)(a2+1)-30
| =a4+3a2+2-30 | =a4+3a2-28 | =(a2-4)(a2+7) | =(a+2)(a-2)(a2+7) |
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举一反三
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