若x(x4+y4)=y5,x2(x+y)≠y3,则x3+y3=______.
题型:填空题难度:一般来源:不详
若x(x4+y4)=y5,x2(x+y)≠y3,则x3+y3=______. |
答案
x5-y5 =x5-x4y+x4y-xy4+xy4-y5 =x5-y5-xy(x3+y3)+xy(x3+y3) ∴-xy(x3+y3)+xy(x3+y3)=0 x3+y3=1. 故答案为:1. |
举一反三
因式分(x+2)(x+3)+x2-4=______. |
在实数范围内分解因式:2x2+3x-1=______. |
把x3-xy2分解因式的结果是( )A.x(x2-y2) | B.x(x-y)2 | C.x(x-y)(x+y) | D.x(x+y)2 |
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计算:20033-20013-6×20032+24×1001=______. |
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