(1)∵(x+1)2-144=0, ∴(x+1)2=144, ∴x+1=±12, 解得:x1=11,x2=-13;
(2)∵3(x-2)2=x(x-2), ∴(x-2)(3x-6-x)=0, ∴(x-2)(2x-6)=0, 即x-2=0或2x-6=0, 解得:x1=2,x2=3;
(3)∵x2-x-=0, ∴3x2-2x-1=0, ∴(3x+1)(x-1)=0, 即3x+1=0或x-1=0, 解得:x1=-,x2=1;
(4)∵(x+2)2-10(x+2)+24=0, ∴(x+2-4)(x+2-6)=0, 即(x-2)(x-4)=0, 即x-2=0或x-4=0, 解得:x1=2,x2=4. |