解: (1)y1=60x(0≤x≤10), y2=﹣100x+600(0≤x≤6) (2)当x=3时,y1=180,y2=300, ∴y2﹣y1=120, 当x=5时y1=300,y2=100, ∴y1﹣y2=200, 当x=8时y1=480,y2=0, ∴y1﹣y2=y1=480. (3)当两车相遇时耗时为x,y1=y2, 解得x=, S=y2﹣y1=﹣160x+600(0≤x≤) S=y1﹣y2=160x﹣600(<x≤6) S=60x(6≤x≤10); (4)由题意得:S=200, ①当0≤x≤时﹣160x+600=200, ∴x= ∴y1=60x=150km. ②当<x<6时160x﹣600=200, ∴x=5, ∴y1=300km, ③当6≤x≤10时60x≥360不合题意. 即:A加油站到甲地距离为150km或300km.
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