如图,已知OC平分∠AOE,OB平分∠AOC,OD平分∠COE,则图中度数等于∠1度数的2倍的角共有______个.
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如图,已知OC平分∠AOE,OB平分∠AOC,OD平分∠COE,则图中度数等于∠1度数的2倍的角共有______个.![魔方格](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118184113-46360.png) |
答案
∵OC平分∠AOE,OB平分∠AOC,OD平分∠COE, ∴∠1=∠BOC=∠COD=∠DOE, ∴∠AOC=∠BOD=∠COE=2∠1. 故答案为3. |
举一反三
若∠AOB=120°,OD平分∠AOB,则∠AOD=______. |
如图,已知OA⊥OD,BO平分∠AOC,∠AOB:∠COD=2:5.求∠AOB的度数.![魔方格](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118184058-57743.png) |
已知:如图,AB⊥CD于点O,∠1=∠2,OE平分∠BOF,∠EOB=55°,求∠DOG的度数.![魔方格](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118184047-39544.png) |
如图,OC是∠AOB的平分线,OD是∠BOC的平分线,若∠AOB=140°,则∠AOD等于( )![魔方格](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118184042-62315.png) |
如图,OA⊥OB,OC平分∠AOB,则∠BOC=______度.![魔方格](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118184039-62212.png) |
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