(1)n(O2)==0.006mol, 一份中:n(CaO2•nH2O)=2n(O2)=0.012mol, n(CaCO3)==0.014mol, n(CaO)=n(CaCO3)-n(CaO2•nH2O)=0.002mol, 2.168g样品中m(CaO)=0.002mol×56g/mol×2=0.224g, 答:2.168g样品中CaO的质量为0.224g, (2)2.168g过氧化钙样品中的质量为2.168g-0.224g, 则2×0.012×(72+18n)=2.168-0.224, n=0.5, 答:样品中CaO2•nH2O的n值为0.5. |