A.H2与F2反应的热化学方程式为:H2(g)+F2(g)=2HF(g) ΔH=-541 kJ |
B.44.8 L HF气体分解成22.4 L H2和22.4 L F2吸收541 kJ的热量 |
C.1 mol H2与1 mol F2反应生成2 mol液态HF放出的热量小于541 kJ |
D.在相同条件下,1 mol H2与1 mol F2的能量总和大于2 mol HF气体的能量 |
A.1个 | B.2个 | C.3个 | D.4个 |
温度/℃ | 200 | 300 | 400 | 500 | 600 |
氨含量/% | 89.9 | 71.0 | 47.0 | 26.4 | 13.8 |
T/℃ | T1 | T2 | T3 |
K | 1/1000 | 1/40 | 25 |
A.CH3OH(l)+3/2O2(g)→CO2(g)+2H2O(l)△H="+725.8" kJ/mol |
B.2CH3OH(l)+3O2(g)→2CO2(g)+4H2O(l)△H=-1452 kJ/mol |
C.2CH3OH(l)+3O2(g)→2CO2(g)+4H2O(l)△H=-725.8 kJ/mol |
D.2CH3OH(l)+3O2(g)→2CO2(g)+4H2O(l)△H="+1452" kJ/mol |
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