【题文】已知函数f(x)=ax3+bsin x+4(a,b∈R),f(lg(log210))=5,则f(lg(lg 2))=( )A.-5B.-1C.3D.4
题型:难度:来源:
【题文】已知函数f(x)=ax
3+bsin x+4(a,b∈R),f(lg(log
210))=5,则f(lg(lg 2))=( )
答案
【答案】C
解析
【解析】因为f(lg(log
2 10))=
![](http://img.shitiku.com.cn/uploads/allimg/20200325/20200325033004-79406.png)
=f(-lg(lg 2))=5,又f(x)+f(-x)=8,所以f(-lg(lg 2))+f(lg(lg 2))=8,所以f(lg(lg 2))=3,故选C.
.
举一反三
【题文】设函数g(x)=x
2-2(x∈R),f(x)=
![](http://img.shitiku.com.cn/uploads/allimg/20200325/20200325032959-83067.png)
则f(x)的值域是( )
A. ∪(1,+∞) |
B.[0,+∞) |
C.![](http://img.shitiku.com.cn/uploads/allimg/20200325/20200325033000-19518.png) |
D. ∪(2,+∞) |
【题文】已知函数
![](http://img.shitiku.com.cn/uploads/allimg/20200325/20200325032949-23507.png)
,则
![](http://img.shitiku.com.cn/uploads/allimg/20200325/20200325032949-77555.png)
的值等于( )
【题文】已知函数f(x)=ax
3+bsin x+4(a,b∈R),f(lg(log
210))=5,则f(lg(lg 2))=( )
【题文】设函数g(x)=x
2-2(x∈R),f(x)=
![](http://img.shitiku.com.cn/uploads/allimg/20200325/20200325032922-37346.png)
则f(x)的值域是( )
A. ∪(1,+∞) |
B.[0,+∞) |
C.![](http://img.shitiku.com.cn/uploads/allimg/20200325/20200325032922-29786.png) |
D. ∪(2,+∞) |
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