【题文】函数y=ln(2x2-3x+1)的单调增区间为_______.
题型:难度:来源:
【题文】函数y=ln(2x2-3x+1)的单调增区间为_______.
答案
【答案】(1,+∞)
解析
【解析】由2x
2-3x+1>0,
得函数的定义域为(-∞,
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104350-32368.png)
)∪(1,+∞).
令t=2x
2-3x+1,则y=lnt
∵t=2x
2-3x+1=2(x-
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104351-18207.png)
)
2-
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104351-31108.png)
,
∴t=2x
2-3x+1的单调增区间为(1,+∞).
又y=lnt在(1,+∞)上是增函数,
∴函数y=ln(2x
2-3x+1)的单调增间为(1,+∞).
举一反三
【题文】已知
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104340-42060.png)
,
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104340-94026.png)
,则( )
【题文】函数
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104317-25361.png)
的定义域为( )
【题文】已知
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104220-33287.png)
则
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104220-73467.png)
=________.
【题文】若
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104052-54862.png)
,
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104052-59013.png)
,则“
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104052-10892.png)
”是“
![](http://img.shitiku.com.cn/uploads/allimg/20200330/20200330104053-72089.png)
”的( )
A.充分不必要条件 | B.必要不充分条件 |
C.充要条件 | D.既不充分又不必要条件 |
【题文】
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