解方程组：{x-1/3=y-3/4=z+2/5 2x-3y+2z=1

题目

解方程组：{x-1/3=y-3/4=z+2/5 2x-3y+2z=1
解方程组：{x-1/3=y-3/4=z+2/5
2x-3y+2z=1

答案

(X-1)/3=(Y-3)/4=(Z+2)/5;2X-3Y+2Z=1
令(X-1)/3=(Y-3)/4=(Z+2)/5=K
则(X-1)/3=K,X=3K+1
同理,Y=4K+3,Z=5K-2
代入2X-3Y+2Z=1中,
2*(3K+1)-3*(4K+3)+2*(5K-2)=1
6K+2-12K-9+10K-4=1
4K=12
K=3
所以
X=3K+1=3*3+1=10
Y=4K+3=4*3+3=15
Z=5K-2=3*5-2=13