如图,设AB=1.O为A在平面BB1D1D的垂足,∠OBA1为所
求.A1O=1/√2.A1B=√2,
sin∠OBA1=A1O/A1B=1/2, ∠OBA1=30°
对角线A1B与对角面BB1DD1所成的角为30°
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