x y m 为实数,且√（x-2m-y）+√(x-4) =√(x+y-6)+√(6-x-y),求2x+3y-m=?

题目

x y m 为实数,且√（x-2m-y）+√(x-4) =√(x+y-6)+√(6-x-y),求2x+3y-m=?

答案

√（x-2m-y）+√(x-4) =√(x+y-6)+√(6-x-y)
x-2m-y≥0
x-4≥0
x+y-6≥0
6-x-y≥0
x=4.y=2,m=1
2x+3y-m=13