分解因式:x3+2x2y+2xy2+y3=______.
题型:填空题难度:一般来源:不详
分解因式:x3+2x2y+2xy2+y3=______. |
答案
x3+2x2y+2xy2+y3=(x3+y3)+(2x2y+2xy2) =(x+y)(x2-xy+y2)+2xy(x+y) =(x+y)(x2+xy+y2) 故答案为:(x+y)(x2+xy+y2) |
举一反三
若正整数a、b、c满足a3+b3+c3-3abc=0,则( )A.a=b=c | B.a=b≠c | C.b=c≠a | D.c两两不等 |
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已知互不相等的实数a,b,c满足a+=b+=c+=t,则t=______. |
已知x<0,x-x-1=-1,则x3+x-3的值是( ) |
设x、y、z是三个互不相等的数,且x+=y+=z+,则xyz=______. |
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