解:(1)(﹣a3)2(﹣a2)3=a6(﹣a6)=﹣a12(2)[(﹣a)(﹣b)2a2b3c]2=(﹣a3b5c)2=a6b10c2(3)=(9××)3=23=8(4)(x3)2÷x2÷x+x3÷(﹣x)2(﹣x2)=x6÷x2÷x+x3÷x2(﹣x2)=x3﹣x3=0
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