计算:(1)|-1|-2+(π-3)0-2-2;(2)[(x-y)2-(x-y)2]÷(-2xy)
题型:解答题难度:一般来源:不详
计算: (1)|-1|-2+(π-3)0-2-2; (2)[(x-y)2-(x-y)2]÷(-2xy) |
答案
(1)原式=1-2+1-=-; (2)原式=(x2-2xy+y2-x2+2xy-y2)÷(-2xy)=0. |
举一反三
(1)(-1)-2+(π-23)0-(-)-1 (2)已知:a+=3,求a2+的值. (3)(9x3y2-6x2y+3xy2)÷(-3xy); (4)先化简再求值:(m+1)2-5(m+1)(m-1)+3(m-1)2,其中m=-. |
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