把下列各式因式分(1)-a2-1+2a=______;(2)2x2y-x3-xy2=______;(3)(x2+1)2-4x2=______;(4)(x+y)2
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把下列各式因式分 (1)-a2-1+2a=______; (2)2x2y-x3-xy2=______; (3)(x2+1)2-4x2=______; (4)(x+y)2-2(x2-y2)+(x-y)2=______. |
答案
(1)原式=-(a-1)2; (2)原式=-x(x-y)2; (3)原式=(x+1)2(x-1)2; (4)原式=(x+y-x+y)2=4y2. |
举一反三
分解因式: (1)a3-a; (2)(x+y)2-12(x+y)+36. |
(1)化简:(x+3y)2+(2x+y)(x-y) (2)分解因式:x3-2x2y+xy2 (3)先化简,再求值.(2xy3+x2y2-5x2y3)÷(-xy2),其中x=1,y=-3. |
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