(1)解:设该专营店第一季度购进A、B两种型号手机的数量分别为x部和y部. 1分 答:该专营店本次购进A、B两种型号手机的数分别为15部和18部.······························································ 4分 (2)解:设第二季度购进A型号手机a部.···················································· 5分 由题意可知:1200a+1000(34-a)≤36000,····················································· 6分 解得:a≤10··························································································· 7分 不等式的最大整数解为10 答:第二季度最多能购A型号手机10部.······················································ 8分 |