如图,AB∥CD,∠CGF=35°,∠AHF=60°,则∠F的度数为______.
题型:不详难度:来源:
如图,AB∥CD,∠CGF=35°,∠AHF=60°,则∠F的度数为______.
![](http://img.shitiku.com.cn/uploads/allimg/20191023/20191023102907-21850.png) |
答案
∵AB∥CD,∠AHF=60°, ∴∠HEG=∠AHF=60°, ∵∠HEF是△EFG的外角, ∴∠F=∠HEG-∠CGF=60°-35°=25°. 故答案为:25°. |
举一反三
如图,已知a∥b,∠1=50°,那么∠2的度数是( )
![](http://img.shitiku.com.cn/uploads/allimg/20191023/20191023102903-49499.png) |
如图,直线a∥b,∠1+∠2=128°,求∠3的度数.
![](http://img.shitiku.com.cn/uploads/allimg/20191023/20191023102901-31469.png) |
如图,把矩形ABCD沿EF折叠,若∠1=50°,则∠AEF等于______.
![](http://img.shitiku.com.cn/uploads/allimg/20191023/20191023102858-12809.png) |
已知:如图,BD平分∠ABC,点E在BC上,EF∥AB.若∠CEF=100°,则∠ABD的度数为( )
![](http://img.shitiku.com.cn/uploads/allimg/20191023/20191023102855-83442.png) |
如图,AB∥CD,∠A=40°,∠D=45°,则∠1的度数为( )
![](http://img.shitiku.com.cn/uploads/allimg/20191023/20191023102850-34117.png) |
最新试题
热门考点