如图,△ABC≌△EFD,那么下列结论错误的是( )A.FC=BDB.DE=BDC.EF∥ABD.AC∥DE
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如图,△ABC≌△EFD,那么下列结论错误的是( )A.FC=BD | B.DE=BD | C.EF∥AB | D.AC∥DE |
![](http://img.shitiku.com.cn/uploads/allimg/20191027/20191027040937-65864.png) |
答案
∵△ABC≌△EFD, ∴DE=AC,∠F=∠B,∠EDF=∠ACB,FD=BC, ∴EF∥AB,AC∥DE,FD-CD=BC-DC, ∴FC=BD,故选项A、C、B错误,选项B正确; 即错误的是选项B, 故选B. |
举一反三
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![](http://img.shitiku.com.cn/uploads/allimg/20191027/20191027040929-22648.png) |
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