解:(1) 由旋转得△ACB≌△DEB ∴BD = BA ∴∠BAD =∠BDA = ∴∠ABD = ∴∠ABC =∠ABD = ∵∠C = ∴∠BAC =·········································································· 5分 (2) ∵BC = 8,AC = 6,∠C = ∴ ∵∠DEB =∠C =且BE = BC = 8,DE ="AC" = 6 ∴AE =" AB" – BE = 2 在Rt△DEA中, 设AD边上的高为h ∴ ∴······················································· 10分 |