如图,AB和CD交于点O,则∠AOC的邻补角是______.∠AOC的对顶角是______,若∠AOC=40°,则∠BOD=______,∠AOD=______
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如图,AB和CD交于点O,则∠AOC的邻补角是______.∠AOC的对顶角是______,若∠AOC=40°,则∠BOD=______,∠AOD=______,∠BOC=______.
![](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118203831-26203.png) |
答案
AB和CD交于点O,则∠AOC的邻补角是∠AOD和∠BOC; ∠AOC的对顶角是∠BOD, ∵∠AOC=40°, ∴∠BOD=∠AOC=40°, ∠AOD=180°-∠AOC=180°-40°=140°, ∠BOC=∠AOD=140°. 故答案为:∠AOD和∠BOC;∠BOD;40°;140°;140°. |
举一反三
如图,直线AB,CD相交于点0,OE平分∠AOD,若∠BOC=80°,则∠AOE=______°.
![](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118203823-56027.png) |
如图,直线y=kx-6经过点A(4,0),直线y=-3x+3与x轴交于点B,且两直线交于点C. (1)求k的值; (2)求△ABC的面积.
![](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118203812-44232.png) |
如图,直线l1的函数解析式为y=2x-2,直线l1与x轴交于点D.直线l2:y=kx+b与x轴交于点A,且经过点B,如图所示.直线l1、l2交于点C(m,2). (1)求点D、点C的坐标; (2)求直线l2的函数解析式; (3)求△ADC的面积; (4)利用函数图象写出关于x、y的二元一次方程组的解.
![](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118203754-40562.png) |
如图,直线AB、CD相交于点O,若∠1=28°,则∠2=______度.
![](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118203750-19507.png) |
如图,当剪子∠AOB增大15°时,∠COD增大______度,其根据是:______.
![](http://img.shitiku.com.cn/uploads/allimg/20191118/20191118203745-99579.png) |
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