(1)卤代烃在碱性醇溶液加热条件下发生了消去反应,生成不饱和烯烃,CH2BrCH3+NaOHCH2=CH2↑+H2O+NaBr,故答案为:CH2Br-CH3+NaOHCH2=CH2↑+H2O+NaBr; (2)由乙烯生成1,2-二溴乙烷,发生了加成反应,CH2=CH2+Br2→CH2BrCH2Br,故答案为:CH2=CH2+Br2→CH2BrCH2Br; (3)卤代烃在碱性水溶液加热条件下发生了取代反应,生成醇:CH2BrCH2Br+2NaOHCH2OHCH2OH+2NaBr,故答案为:CH2BrCH2Br+2NaOHCH2OHCH2OH+2NaBr; (4)卤代烃在碱性水溶液加热条件下发生取代反应,由溴乙烷变成乙醇,生成乙醇与溴化钠, 方程式为CH3CH2Br+NaOH CH3CH2OH+NaBr, 故答案为:CH3CH2Br+NaOH CH3CH2OH+NaBr; (5)1,2-二溴乙烷,在碱性醇溶液加热条件下发生了消去反应, 方程式为CH2BrCH2Br+2NaOHCH≡CH↑+2NaBr+2H2O, 故答案为:CH2BrCH2Br+2NaOHCH≡CH↑+2NaBr+2H2O; |