设集合A={x|0<x<9,x是质数},B={x|0<x<9,x∈N},则满足条件A⊊S⊆B的集合S共有( )个.A.7B.8C.15D.16
题型:单选题难度:简单来源:不详
设集合A={x|0<x<9,x是质数},B={x|0<x<9,x∈N},则满足条件A⊊S⊆B的集合S共有( )个. |
答案
∵集合A={x|0<x<9,x是质数}={2,3,5,7}, B={x|0<x<9,x∈N}={1,2,3,4,5,6,7,8}, 又∵集合S满足条件A⊊S⊆B ∴S={1,2,3,5,7},或S={2,3,4,5,7},或S={2,3,5,6,7或},或S={2,3,5,7,8}, 或S={1,2,3,4,5,7},或S={1,2,3,5,6,7},或S={1,2,3,5,7,8}, 或S={2,3,4,5,6,7},或S={2,3,4,5,7,8},或S={2,3,5,6,7,8}, 或S={1,2,3,4,5,6,7},或S={1,2,3,4,5,7,8},或S={1,2,3,5,6,7,8}, 或S={2,3,4,5,6,7,8},或S={1,2,3,4,5,6,7,8}, 故满足条件的集合S共有15个 故选C |
举一反三
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