设全集U={0,1,2,3,4},集合A={0,1,2},集合B={2,3},则(CUA)∪B=( )A.∅B.{1,2,3,4}C.{0,1,2,3,4}D
题型:单选题难度:简单来源:深圳一模
设全集U={0,1,2,3,4},集合A={0,1,2},集合B={2,3},则(CUA)∪B=( )A.∅ | B.{1,2,3,4} | C.{0,1,2,3,4} | D.{2,3,4} |
|
答案
由全集U={0,1,2,3,4},集合A={0,1,2}, 则CUA={3,4}, 又因为集合B={2,3}, 则(CUA)∪B={2,3,4}. 故选D. |
举一反三
已知函数f(x)=+的定义域为集合A,B={x丨m<x-m<9}. (1)若m=0,求A∩B,A∪B; (2)若A∩B=B,求所有满足条件的m的集合. |
设集合A∩{-1,0,1}={0,1},A∪{-2,0,2}={-2,0,1,2},则满足上述条件的集合A的个数为( ) |
已知集合A={x|y=log2(x-1)},B={y|y=()x,x≤0},则A∩B等于______. |
已知集合A={x∈R题型:x+2|<3}集合B={x∈R|(x-m)(x-2)<0},且A∩B=(-1,n),则m,n的值为( ) |
难度:|
查看答案