设U={0,1,2,3,4},A={0,1,2,3},B={2,3,4},则 (C∪A)∪(C∪B)=( )A.{0,1,2,3,4}B.{0,1,4}C.{
题型:单选题难度:简单来源:不详
设U={0,1,2,3,4},A={0,1,2,3},B={2,3,4},则 (C∪A)∪(C∪B)=( )A.{0,1,2,3,4} | B.{0,1,4} | C.{0,1} | D.{0} |
|
答案
∵CUA={4},CUB={0,1}, ∴(CUA)∪(CUB)={4}∪{0,1}={0,1,4}. 故选B. |
举一反三
设全集U={1,2,3,4,5,6,7,8},A={2,4,5},B={1,2,6},则集合{3,7,8}是( )A.(C∪A)∩(C∪B) | B.(C∪A)∪(C∪B) | C.A∪B | D.A∩B |
|
设全集为U,用集合A、B、C的交、并、补集符号表图中的阴影部分.
(1)______ (2)______. |
已知全集U={0,2,4,6,8,10},集合A={2,4,6},B={10},则CUA∪B为______. |
集合A={0,1,2,3,4,5},B={1,3,6,9},C={3,7,8},(A∩B)∪C=______. |
图中能表示集合(A∪C)∩(CUB)的阴影部分是( ) |
最新试题
热门考点