f(x)=2x3-3(a+1)x2+6ax-2(a>0且a≠1),(Ⅰ)当a=2时,求函数f(x)的单调区间;(Ⅱ)若f(x)在区间[0,2]内有三个零点,求a的取值范围。注:a3-3a2+2=(a-1)(a2-2a-2)
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A.f(0)+f(2)<2f(1)B.f(0)+f(2)≤2f(1)C.f(0)+f(2)≥2f(1)D.f(0)+f(2)>2f(1)
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