【题文】设集合M={x|-3<x<2},N={x|1≤x≤3},则MN=( )A.[2,3]B.[1,2]C.(
题型:难度:来源:
【题文】设集合M={x|-3<x<2},N={x|1≤x≤3},则M
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133403-88378.png)
N=( )
A.[2,3] | B.[1,2] | C.(-3,3] | D.[1,2) |
答案
【答案】C
解析
【解析】
试题分析:根据所给集合
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133403-57714.png)
都是无限数集,利用数轴表示出集合
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133403-57714.png)
,找出并集
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133403-99704.png)
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133403-12525.png)
考点:1.集合的交集、并集、补集运算;2.运算工具(韦恩图、数轴、平面直角坐标系).
举一反三
【题文】图中阴影部分所表示的集合是( )
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133357-47081.jpg)
【题文】方程
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133349-54550.png)
的解集为M,方程
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133350-45140.png)
的解集为N,且
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133350-33067.png)
,那么
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133350-16923.png)
_________.
【题文】(本小题满分12分)设全集
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133334-52111.png)
,集合
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133334-98546.png)
(1)求
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133334-65732.png)
,
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133335-86352.png)
;
(2)若
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133335-69533.png)
,求实数
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133335-31815.png)
的取值范围.
【题文】全集
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133311-46140.png)
,集合
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133311-69062.png)
,
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133312-95007.png)
,则
![](http://img.shitiku.com.cn/uploads/allimg/20200322/20200322133312-66711.png)
( )
A.{0} | B.{-3,-4} | C.{-1,-2} | D.φ |
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