如何计算一元多次方程的所有解（实数和虚数所有的解）?

题目

如何计算一元多次方程的所有解（实数和虚数所有的解）?
比如：
8721x^15 + 8721x^14 + 8721x^13 + 8721x^12 + 8721x^11 = 46110
需要所有的15个解.

答案

建议你用MATLAB或者MATHEMITICA软件算,三次方程已经不好算了啊.
MATLAB下面输入：
solve('x^15+x^14+x^13+x^12+x^11=46110/8721')
得到结果为：其中一个实数解,十四个复数解.
ans =
[ -1.1152169330840513044678969904181-.25708671244866928739326424594244*i]
[ -1.1152169330840513044678969904181+.25708671244866928739326424594244*i]
[ -.98139036033570601454028110913317-.69056221333398920127100845037959*i]
[ -.98139036033570601454028110913317+.69056221333398920127100845037959*i]
[ -.62708924488203044214406216030245-.95186741263493297628489107577268*i]
[ -.62708924488203044214406216030245+.95186741263493297628489107577268*i]
[ -.14214372312581642017140380564159-1.1086554107767978206603262357566*i]
[ -.14214372312581642017140380564159+1.1086554107767978206603262357566*i]
[ .31348796169964275368354468747476-1.1275703015018958584329556590608*i]
[ .31348796169964275368354468747476+1.1275703015018958584329556590608*i]
[ .64318720990196283244330241658993-.88609282225033714508577942917884*i]
[ .64318720990196283244330241658993+.88609282225033714508577942917884*i]
[ .90701279479658833013435965915705-.47383409159259900230187916490365*i]
[ .90701279479658833013435965915705+.47383409159259900230187916490365*i]
[ 1.0043045900588205301248746045470]