计算:(1)5s2t-2s2t;(2)-22+20-|-3|×(-3)-1;(3)(a2b)(-2ab2)(-0.5a4b5);(4)4m2-(-2m+3)(-
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计算: (1)5s2t-2s2t; (2)-22+20-|-3|×(-3)-1; (3)(a2b)(-2ab2)(-0.5a4b5); (4)4m2-(-2m+3)(-2m-3). |
答案
(1)原式=(5-2)s2t =3s2t;
(2)原式=-4+1-3×(-) =-4+1+1 =-2;
(3)原式=(-2)×(-0.5)a7b8 =a7b8;
(4)原式=4m2-(-2m)2+9 =9. |
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