分解因式:(x+1)(x+2)(x+3)-6×7×8=______.
题型:填空题难度:一般来源:不详
分解因式:(x+1)(x+2)(x+3)-6×7×8=______. |
答案
(x+1)(x+2)(x+3)-6×7×8 =x3+6x2+11x+6-336 =x3+6x2+11x-330 =x3-5x2+11x2-55x+66x-330 =x2(x-5)+11x(x-5)+66(x-5) =(x-5)(x2+11x+66). 故答案为(x-5)(x2+11x+66). |
举一反三
已知a+b=2,ab=1,则a2b+2a2b2+ab2的值等于( ) |
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