解法一:∵BC是⊙O的切线, ∴. 在Rt△ABC中,∵,∴. ∴.··············································································· 3分 在Rt△AOD中,,∴.···· 6分 ∵, ∴.··························································· 8分 解法二:连接BE.∵AB为直径,∴. ∴.∴.·········································· 3分 在Rt△ABC中,∵, ∴. ∴.························································ 6分 ∵, ∴.·················································· 8分 |