解:∵OA丄OB,OC丄OD,∴∠AOB=∠COD=90°,∵OE为∠BOD的平分线,∴∠BOD=44°,∴∠AOC=360°﹣(∠AOB+∠COD+∠BOD),=360°﹣(90°+90°+44°),=136 °.
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