limx→0(1x2-x-2x2-2x)=______．

题型：西城区二模难度：来源：

lim

x→0

(

1

x2-x

-

2

x2-2x

)=______．

答案

lim

x→0

(

1

x2-x

-

2

x2-2x

)=

lim

x→0

[

1

x(x-1)

-

2

x(x-2)

]
=

lim

x→0

x-2-2x+2

x(x-1)(x-2)

=

lim

x→0

-1

(x-1)(x-2)

=-

1

2

．
故答案为：-

1

2

．