解法一: , 依题设知,. (Ⅰ)连结交于点,则. 由三垂线定理知,.······························································· 3分 在平面内,连结交于点, 由于, 故,, 与互余. 于是. 与平面内两条相交直线都垂直, 所以平面.········································································· 6分 (Ⅱ)作,垂足为,连结.由三垂线定理知, 故是二面角的平面角.··············································· 8分 , ,. ,. 又,. . 所以二面角的大小为.··············· 12分 解法二: 以为坐标原点,射线为轴的正半轴, 建立如图所示直角坐标系. 依题设,. , .······························································· 3分 (Ⅰ)因为,, 故,. 又, 所以平面.········································································· 6分 (Ⅱ)设向量是平面的法向量,则 ,. 故,. 令,则,,.·············································· 9分 等于二面角的平面角, . 所以二面角的大小为. |