因式分(1)x2y-2xy2+y3;(2)(x+2y)2-y2.
题型:解答题难度:一般来源:不详
因式分 (1)x2y-2xy2+y3; (2)(x+2y)2-y2. |
答案
(1)x2y-2xy2+y3, =y(x2-2xy+y2), =y(x-y)2;
(2)(x+2y)2-y2, =(x+2y+y)(x+2y-y), =(x+3y)(x+y). |
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