设全集U={0,1,2,3,4},集合A={1,2,3},集合B={2,3,4},则A∩∁UB=( )A.{1}B.{0,1}C.{0,1,2,3}D.{0,
题型:单选题难度:一般来源:不详
设全集U={0,1,2,3,4},集合A={1,2,3},集合B={2,3,4},则A∩∁UB=( )A.{1} | B.{0,1} | C.{0,1,2,3} | D.{0,1,2,3,4} |
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答案
∵全集U={0,1,2,3,4}, 集合A={1,2,3}, 集合B={2,3,4}, ∴A∩∁UB={1,2,3}∩{0,1} ={1}. 故选A. |
举一反三
已知集合A={x|x<2},B={x|-1≤x≤3},则A∪B=( )A.{x|x≤3} | B.{x|x≥-1} | C.{x|-1≤x<2} | D.{x|-1≤x≤3} |
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设集合A={x|x>3},B={x|>0},则A∩B=( )A.∅ | B.(3,4) | C.(-2,1) | D.(4,+∞) |
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设全集U=R,集合A={x|x2-2x-3≤0},B={x|x2-4x≤0}, (1)求A∩B,A∪B; (2)求(∁UA)∩(∁UB). |
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