分解因式:x2y+xy2-x2-y2-3xy+2x+2y-1=______.
题型:填空题难度:一般来源:不详
分解因式:x2y+xy2-x2-y2-3xy+2x+2y-1=______. |
答案
x2y+xy2-x2-y2-3xy+2x+2y-1 =x2y+xy2-xy-x2-y2-2xy+2x+2y-1 =xy(x+y-1)-[(x+y)2-2(x+y)+1] =xy(x+y-1)-(x+y-1)2 =(x+y-1)(xy-x-y+1) =(x+y-1)(y-1)(x-1). 故答案为:(x+y-1)(y-1)(x-1). |
举一反三
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